javascript – Regex to match text between variable string and quotation marks

I am trying to write up regex to match text that appears after the word Example, in some cases this could be written as Examples.

I want to return all the text that appears between Examples(s) and [text], ending with the last the quotation marks.

Sample Text:

"In this kata you are required to, given a string, replace every letter with its position in the alphabet.  If anything in the text isn't a letter, ignore it and don't return it.  `'a' = 1`, `'b' = 2`, etc.  ## Example <!-- unlisted languages will use the first entry. please keep python up top. -->  ```python alphabet_position('The sunset sets at twelve o' clock.') ```  ```crystal alphabet_position('The sunset sets at twelve o' clock.') ``` Should return `20 8 5 19 21 14 19 5 20 19 5 20 19 1 20 20 23 5 12 22 5 15 3 12 15 3 11` ( as a string )"

Expected output:

<!-- unlisted languages will use the first entry. please keep python up top. -->  ```python alphabet_position('The sunset sets at twelve o' clock.') ```

Attempted solution:

const matched = test.match('Example(.)(.*)```(.*)```')

However this returns nothing (blank)