In a 32 bit compiler if you add one maximum value of signed it you will get

Core Answer:

The minimum value of a signed 32-bit integer.

Reasons and Explanations:

Reason 1: Integer Overflow: In a 32-bit signed integer system, the maximum value is 2,147,483,647 (2³¹ – 1). Adding 1 to this value exceeds the representable range, causing an integer overflow.

Reason 2: Two’s Complement Representation: Signed integers are typically represented using two’s complement. In this system, adding 1 to the maximum positive value results in a bit pattern that represents the most negative value (-2,147,483,648 or -2³¹).

Summary:

Adding one to the maximum value of a signed 32-bit integer in a 32-bit compiler results in an integer overflow, yielding the minimum value of a signed 32-bit integer due to the two’s complement representation.