In 32 bit compiler if we add one to the maximum value of signed int we will get

Core Answer:

The minimum value of a signed integer.

Reasons and Explanations:

Reason 1: Integer Overflow: In a 32-bit compiler, a signed integer uses 32 bits to represent both positive and negative numbers. The maximum value is 2,147,483,647 (2³¹ – 1). Adding 1 to this exceeds the representable range, causing an overflow.

Reason 2: Two’s Complement Representation: Signed integers are typically represented using two’s complement. When an overflow occurs, the result wraps around from the maximum positive value to the minimum negative value (-2,147,483,648 or -2³¹).

Summary:

Adding one to the maximum value of a signed integer in a 32-bit compiler results in an integer overflow, producing the minimum value of a signed integer due to the cyclical nature of two’s complement representation.