In 32 bit compiler if one is added to maximum value of signed int

Core Answer:

The result will be the minimum value of a signed integer.

Reasons and Explanations:

Reason 1: Integer Overflow: In a 32-bit compiler, a signed integer typically uses 32 bits to represent both positive and negative numbers. The maximum value is 2,147,483,647 (2³¹ – 1). Adding 1 to this exceeds the representable range, causing an integer overflow.

Reason 2: Two’s Complement Representation: Signed integers are usually stored using two’s complement representation. In this system, the most significant bit (MSB) indicates the sign (0 for positive, 1 for negative). When an overflow occurs, the result wraps around from the maximum positive value to the minimum negative value (-2,147,483,648 or -2³¹).

Summary:

Adding 1 to the maximum value of a signed integer in a 32-bit compiler results in an integer overflow, causing the value to wrap around to the minimum value of a signed integer due to the two’s complement representation.