Do filters break when cutoff is at nyquist ? (in: DSP and Plugin Devel…)

By: mystran
13 Aug 21:26

You can’t put poles above Nyquist. If you try you’ll typically end up with infinities or NaNs (either in the coefficient computation, or due to an unstable filter).

You can attempt to fit a response to a filter that would have it’s poles at a higher frequencies (tends to be most useful for EQs and such) or you can oversample, which pushes the Nyquist higher so we’re no longer above it. You can also cheat and not compute your coefficient correctly, in which case your actual cutoff is lower than …

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